pound-force foot/pound/°R to joule/kilogram/°C
Please provide values below to convert pound-force foot/pound/°R to joule/kilogram/°C [J/(kg*°C)], or change ↔.
pound-force foot/pound/°R
Definition: A unit of specific heat, used in imperial systems, based on pound-force and Rankine temperature scale.
Historyandorigin: Used in older thermodynamics in the imperial system, especially in North America.
CurrentUse: Primarily found in older heating and industrial systems in the US.
funfact: The Rankine scale is used less today, but it’s still relevant in some engineering applications for absolute temperature!
joule/kilogram/°C [J/(kg*°C)]
Definition: The same as J/(kg*K), but using degrees Celsius instead of Kelvin as the temperature unit.
Historyandorigin: Part of the SI system, derived from the metric system for measuring energy changes.
CurrentUse: Used in chemistry, physics, and engineering to analyze temperature effects in materials.
funfact: For many substances, specific heat is almost the same whether measured in °C or K, thanks to the proportionality!
pound-force foot/pound/°R to joule/kilogram/°C [J/(kg*°C)] Conversion Table
| 1 pound-force foot/pound/°R | 5.380320456 joule/kilogram/°C [J/(kg*°C)] |
| 2 pound-force foot/pound/°R | 10.760640912 joule/kilogram/°C [J/(kg*°C)] |
| 3 pound-force foot/pound/°R | 16.140961368 joule/kilogram/°C [J/(kg*°C)] |
| 5 pound-force foot/pound/°R | 26.90160228 joule/kilogram/°C [J/(kg*°C)] |
| 10 pound-force foot/pound/°R | 53.80320456 joule/kilogram/°C [J/(kg*°C)] |
| 50 pound-force foot/pound/°R | 269.0160228 joule/kilogram/°C [J/(kg*°C)] |
| 100 pound-force foot/pound/°R | 538.0320456 joule/kilogram/°C [J/(kg*°C)] |
| 1000 pound-force foot/pound/°R | 5380.320456 joule/kilogram/°C [J/(kg*°C)] |
| 10000 pound-force foot/pound/°R | 53803.20456 joule/kilogram/°C [J/(kg*°C)] |
| 100000 pound-force foot/pound/°R | 538032.0456 joule/kilogram/°C [J/(kg*°C)] |
| 1000000 pound-force foot/pound/°R | 5380320.456 joule/kilogram/°C [J/(kg*°C)] |
How to Convert pound-force foot/pound/°R to joule/kilogram/°C
1 pound-force foot/pound/°R = 5.380320456 joule/kilogram/°C [J/(kg*°C)]
1 joule/kilogram/°C [J/(kg*°C)] = 0.1858625352 pound-force foot/pound/°R
we use cross multiplication method
pound-force foot/pound/°R → joule/kilogram/°C [J/(kg*°C)]
1 → 5.380320456
1.5 → ?( suppose x)
=>1.5*5.380320456=1*x
by simplifying
x=8.070480684