joule/kilogram/°C to pound-force foot/pound/°R
Please provide values below to convert joule/kilogram/°C [J/(kg*°C)] to pound-force foot/pound/°R, or change ↔.
joule/kilogram/°C [J/(kg*°C)]
Definition: The same as J/(kg*K), but using degrees Celsius instead of Kelvin as the temperature unit.
Historyandorigin: Part of the SI system, derived from the metric system for measuring energy changes.
CurrentUse: Used in chemistry, physics, and engineering to analyze temperature effects in materials.
funfact: For many substances, specific heat is almost the same whether measured in °C or K, thanks to the proportionality!
pound-force foot/pound/°R
Definition: A unit of specific heat, used in imperial systems, based on pound-force and Rankine temperature scale.
Historyandorigin: Used in older thermodynamics in the imperial system, especially in North America.
CurrentUse: Primarily found in older heating and industrial systems in the US.
funfact: The Rankine scale is used less today, but it’s still relevant in some engineering applications for absolute temperature!
joule/kilogram/°C [J/(kg*°C)] to pound-force foot/pound/°R Conversion Table
| 1 joule/kilogram/°C [J/(kg*°C)] | 0.1858625352 pound-force foot/pound/°R |
| 2 joule/kilogram/°C [J/(kg*°C)] | 0.3717250703 pound-force foot/pound/°R |
| 3 joule/kilogram/°C [J/(kg*°C)] | 0.5575876055 pound-force foot/pound/°R |
| 5 joule/kilogram/°C [J/(kg*°C)] | 0.9293126759 pound-force foot/pound/°R |
| 10 joule/kilogram/°C [J/(kg*°C)] | 1.8586253517 pound-force foot/pound/°R |
| 50 joule/kilogram/°C [J/(kg*°C)] | 9.2931267587 pound-force foot/pound/°R |
| 100 joule/kilogram/°C [J/(kg*°C)] | 18.586253517 pound-force foot/pound/°R |
| 1000 joule/kilogram/°C [J/(kg*°C)] | 185.86253517 pound-force foot/pound/°R |
| 10000 joule/kilogram/°C [J/(kg*°C)] | 1858.6253517 pound-force foot/pound/°R |
| 100000 joule/kilogram/°C [J/(kg*°C)] | 18586.253517 pound-force foot/pound/°R |
| 1000000 joule/kilogram/°C [J/(kg*°C)] | 185862.53517 pound-force foot/pound/°R |
How to Convert joule/kilogram/°C to pound-force foot/pound/°R
1 joule/kilogram/°C [J/(kg*°C)] = 0.1858625352 pound-force foot/pound/°R
1 pound-force foot/pound/°R = 5.380320456 joule/kilogram/°C [J/(kg*°C)]
we use cross multiplication method
joule/kilogram/°C [J/(kg*°C)] → pound-force foot/pound/°R
1 → 0.1858625352
1.5 → ?( suppose x)
=>1.5*0.1858625352=1*x
by simplifying
x=0.2787938028