pound-force foot/pound/°R to joule/gram/°C
Please provide values below to convert pound-force foot/pound/°R to joule/gram/°C [J/(g*°C)], or change ↔.
pound-force foot/pound/°R
Definition: A unit of specific heat, used in imperial systems, based on pound-force and Rankine temperature scale.
Historyandorigin: Used in older thermodynamics in the imperial system, especially in North America.
CurrentUse: Primarily found in older heating and industrial systems in the US.
funfact: The Rankine scale is used less today, but it’s still relevant in some engineering applications for absolute temperature!
joule/gram/°C [J/(g*°C)]
Definition: A smaller unit of specific heat, useful for measuring heat capacity in grams.
Historyandorigin: A more precise measurement for small quantities of materials, based on the Joule.
CurrentUse: Found in laboratory settings or when dealing with small sample sizes in material analysis.
funfact: A small sample with high specific heat can store a significant amount of thermal energy!
pound-force foot/pound/°R to joule/gram/°C [J/(g*°C)] Conversion Table
| 1 pound-force foot/pound/°R | 0.0053803205 joule/gram/°C [J/(g*°C)] |
| 2 pound-force foot/pound/°R | 0.0107606409 joule/gram/°C [J/(g*°C)] |
| 3 pound-force foot/pound/°R | 0.0161409614 joule/gram/°C [J/(g*°C)] |
| 5 pound-force foot/pound/°R | 0.0269016023 joule/gram/°C [J/(g*°C)] |
| 10 pound-force foot/pound/°R | 0.0538032046 joule/gram/°C [J/(g*°C)] |
| 50 pound-force foot/pound/°R | 0.2690160228 joule/gram/°C [J/(g*°C)] |
| 100 pound-force foot/pound/°R | 0.5380320456 joule/gram/°C [J/(g*°C)] |
| 1000 pound-force foot/pound/°R | 5.380320456 joule/gram/°C [J/(g*°C)] |
| 10000 pound-force foot/pound/°R | 53.80320456 joule/gram/°C [J/(g*°C)] |
| 100000 pound-force foot/pound/°R | 538.0320456 joule/gram/°C [J/(g*°C)] |
| 1000000 pound-force foot/pound/°R | 5380.320456 joule/gram/°C [J/(g*°C)] |
How to Convert pound-force foot/pound/°R to joule/gram/°C
1 pound-force foot/pound/°R = 0.0053803205 joule/gram/°C [J/(g*°C)]
1 joule/gram/°C [J/(g*°C)] = 185.86253517 pound-force foot/pound/°R
we use cross multiplication method
pound-force foot/pound/°R → joule/gram/°C [J/(g*°C)]
1 → 0.0053803205
1.5 → ?( suppose x)
=>1.5*0.0053803205=1*x
by simplifying
x=0.0080704807