joule/gram/°C to pound-force foot/pound/°R
Please provide values below to convert joule/gram/°C [J/(g*°C)] to pound-force foot/pound/°R, or change ↔.
joule/gram/°C [J/(g*°C)]
Definition: A smaller unit of specific heat, useful for measuring heat capacity in grams.
Historyandorigin: A more precise measurement for small quantities of materials, based on the Joule.
CurrentUse: Found in laboratory settings or when dealing with small sample sizes in material analysis.
funfact: A small sample with high specific heat can store a significant amount of thermal energy!
pound-force foot/pound/°R
Definition: A unit of specific heat, used in imperial systems, based on pound-force and Rankine temperature scale.
Historyandorigin: Used in older thermodynamics in the imperial system, especially in North America.
CurrentUse: Primarily found in older heating and industrial systems in the US.
funfact: The Rankine scale is used less today, but it’s still relevant in some engineering applications for absolute temperature!
joule/gram/°C [J/(g*°C)] to pound-force foot/pound/°R Conversion Table
1 joule/gram/°C [J/(g*°C)] | 185.86253517 pound-force foot/pound/°R |
2 joule/gram/°C [J/(g*°C)] | 371.72507035 pound-force foot/pound/°R |
3 joule/gram/°C [J/(g*°C)] | 557.58760552 pound-force foot/pound/°R |
5 joule/gram/°C [J/(g*°C)] | 929.31267587 pound-force foot/pound/°R |
10 joule/gram/°C [J/(g*°C)] | 1858.6253517 pound-force foot/pound/°R |
50 joule/gram/°C [J/(g*°C)] | 9293.1267587 pound-force foot/pound/°R |
100 joule/gram/°C [J/(g*°C)] | 18586.253517 pound-force foot/pound/°R |
1000 joule/gram/°C [J/(g*°C)] | 185862.53517 pound-force foot/pound/°R |
10000 joule/gram/°C [J/(g*°C)] | 1858625.3517 pound-force foot/pound/°R |
100000 joule/gram/°C [J/(g*°C)] | 18586253.517 pound-force foot/pound/°R |
1000000 joule/gram/°C [J/(g*°C)] | 185862535.17 pound-force foot/pound/°R |
How to Convert joule/gram/°C to pound-force foot/pound/°R
1 joule/gram/°C [J/(g*°C)] = 185.86253517 pound-force foot/pound/°R
1 pound-force foot/pound/°R = 0.0053803205 joule/gram/°C [J/(g*°C)]
we use cross multiplication method
joule/gram/°C [J/(g*°C)] → pound-force foot/pound/°R
1 → 185.86253517
1.5 → ?( suppose x)
=>1.5*185.86253517=1*x
by simplifying
x=278.79380276