joule/gram/°C to kilocalorie (IT)/kilogram/°C
Please provide values below to convert joule/gram/°C [J/(g*°C)] to kilocalorie (IT)/kilogram/°C, or change ↔.
joule/gram/°C [J/(g*°C)]
Definition: A smaller unit of specific heat, useful for measuring heat capacity in grams.
Historyandorigin: A more precise measurement for small quantities of materials, based on the Joule.
CurrentUse: Found in laboratory settings or when dealing with small sample sizes in material analysis.
funfact: A small sample with high specific heat can store a significant amount of thermal energy!
kilocalorie (IT)/kilogram/°C
Definition: The specific heat in terms of kilocalories per kilogram per degree Celsius.
Historyandorigin: Kilocalories were once the preferred unit for food energy and thermodynamic analysis.
CurrentUse: Used in nutrition and energy studies to measure heat required for large-scale systems.
funfact: The kilocalorie is often used in food labeling, where it’s simply called 'calories' in everyday use!
joule/gram/°C [J/(g*°C)] to kilocalorie (IT)/kilogram/°C Conversion Table
1 joule/gram/°C [J/(g*°C)] | 0.2388458966 kilocalorie (IT)/kilogram/°C |
2 joule/gram/°C [J/(g*°C)] | 0.4776917933 kilocalorie (IT)/kilogram/°C |
3 joule/gram/°C [J/(g*°C)] | 0.7165376899 kilocalorie (IT)/kilogram/°C |
5 joule/gram/°C [J/(g*°C)] | 1.1942294831 kilocalorie (IT)/kilogram/°C |
10 joule/gram/°C [J/(g*°C)] | 2.3884589663 kilocalorie (IT)/kilogram/°C |
50 joule/gram/°C [J/(g*°C)] | 11.942294831 kilocalorie (IT)/kilogram/°C |
100 joule/gram/°C [J/(g*°C)] | 23.884589663 kilocalorie (IT)/kilogram/°C |
1000 joule/gram/°C [J/(g*°C)] | 238.84589663 kilocalorie (IT)/kilogram/°C |
10000 joule/gram/°C [J/(g*°C)] | 2388.4589663 kilocalorie (IT)/kilogram/°C |
100000 joule/gram/°C [J/(g*°C)] | 23884.589663 kilocalorie (IT)/kilogram/°C |
1000000 joule/gram/°C [J/(g*°C)] | 238845.89663 kilocalorie (IT)/kilogram/°C |
How to Convert joule/gram/°C to kilocalorie (IT)/kilogram/°C
1 joule/gram/°C [J/(g*°C)] = 0.2388458966 kilocalorie (IT)/kilogram/°C
1 kilocalorie (IT)/kilogram/°C = 4.1868 joule/gram/°C [J/(g*°C)]
we use cross multiplication method
joule/gram/°C [J/(g*°C)] → kilocalorie (IT)/kilogram/°C
1 → 0.2388458966
1.5 → ?( suppose x)
=>1.5*0.2388458966=1*x
by simplifying
x=0.3582688449