kilocalorie (IT)/kilogram/°C to joule/gram/°C
Please provide values below to convert kilocalorie (IT)/kilogram/°C to joule/gram/°C [J/(g*°C)], or change ↔.
kilocalorie (IT)/kilogram/°C
Definition: The specific heat in terms of kilocalories per kilogram per degree Celsius.
Historyandorigin: Kilocalories were once the preferred unit for food energy and thermodynamic analysis.
CurrentUse: Used in nutrition and energy studies to measure heat required for large-scale systems.
funfact: The kilocalorie is often used in food labeling, where it’s simply called 'calories' in everyday use!
joule/gram/°C [J/(g*°C)]
Definition: A smaller unit of specific heat, useful for measuring heat capacity in grams.
Historyandorigin: A more precise measurement for small quantities of materials, based on the Joule.
CurrentUse: Found in laboratory settings or when dealing with small sample sizes in material analysis.
funfact: A small sample with high specific heat can store a significant amount of thermal energy!
kilocalorie (IT)/kilogram/°C to joule/gram/°C [J/(g*°C)] Conversion Table
| 1 kilocalorie (IT)/kilogram/°C | 4.1868 joule/gram/°C [J/(g*°C)] |
| 2 kilocalorie (IT)/kilogram/°C | 8.3736 joule/gram/°C [J/(g*°C)] |
| 3 kilocalorie (IT)/kilogram/°C | 12.5604 joule/gram/°C [J/(g*°C)] |
| 5 kilocalorie (IT)/kilogram/°C | 20.934 joule/gram/°C [J/(g*°C)] |
| 10 kilocalorie (IT)/kilogram/°C | 41.868 joule/gram/°C [J/(g*°C)] |
| 50 kilocalorie (IT)/kilogram/°C | 209.34 joule/gram/°C [J/(g*°C)] |
| 100 kilocalorie (IT)/kilogram/°C | 418.68 joule/gram/°C [J/(g*°C)] |
| 1000 kilocalorie (IT)/kilogram/°C | 4186.8 joule/gram/°C [J/(g*°C)] |
| 10000 kilocalorie (IT)/kilogram/°C | 41868 joule/gram/°C [J/(g*°C)] |
| 100000 kilocalorie (IT)/kilogram/°C | 418680 joule/gram/°C [J/(g*°C)] |
| 1000000 kilocalorie (IT)/kilogram/°C | 4186800 joule/gram/°C [J/(g*°C)] |
How to Convert kilocalorie (IT)/kilogram/°C to joule/gram/°C
1 kilocalorie (IT)/kilogram/°C = 4.1868 joule/gram/°C [J/(g*°C)]
1 joule/gram/°C [J/(g*°C)] = 0.2388458966 kilocalorie (IT)/kilogram/°C
we use cross multiplication method
kilocalorie (IT)/kilogram/°C → joule/gram/°C [J/(g*°C)]
1 → 4.1868
1.5 → ?( suppose x)
=>1.5*4.1868=1*x
by simplifying
x=6.2802