pound-force foot/pound/°R to calorie (IT)/gram/°F
Please provide values below to convert pound-force foot/pound/°R to calorie (IT)/gram/°F, or change ↔.
pound-force foot/pound/°R
Definition: A unit of specific heat, used in imperial systems, based on pound-force and Rankine temperature scale.
Historyandorigin: Used in older thermodynamics in the imperial system, especially in North America.
CurrentUse: Primarily found in older heating and industrial systems in the US.
funfact: The Rankine scale is used less today, but it’s still relevant in some engineering applications for absolute temperature!
calorie (IT)/gram/°F
Definition: Similar to the calorie (IT)/gram/°C, but using Fahrenheit for the temperature scale.
Historyandorigin: This unit was more common before the widespread adoption of Celsius for scientific measurements.
CurrentUse: Still found in some legacy systems for heat transfer calculations, particularly in older texts.
funfact: Though less common today, Fahrenheit-based calories were widely used in North America!
pound-force foot/pound/°R to calorie (IT)/gram/°F Conversion Table
| 1 pound-force foot/pound/°R | 0.0012850675 calorie (IT)/gram/°F |
| 2 pound-force foot/pound/°R | 0.0025701349 calorie (IT)/gram/°F |
| 3 pound-force foot/pound/°R | 0.0038552024 calorie (IT)/gram/°F |
| 5 pound-force foot/pound/°R | 0.0064253373 calorie (IT)/gram/°F |
| 10 pound-force foot/pound/°R | 0.0128506746 calorie (IT)/gram/°F |
| 50 pound-force foot/pound/°R | 0.0642533732 calorie (IT)/gram/°F |
| 100 pound-force foot/pound/°R | 0.1285067463 calorie (IT)/gram/°F |
| 1000 pound-force foot/pound/°R | 1.2850674635 calorie (IT)/gram/°F |
| 10000 pound-force foot/pound/°R | 12.850674635 calorie (IT)/gram/°F |
| 100000 pound-force foot/pound/°R | 128.50674635 calorie (IT)/gram/°F |
| 1000000 pound-force foot/pound/°R | 1285.0674635 calorie (IT)/gram/°F |
How to Convert pound-force foot/pound/°R to calorie (IT)/gram/°F
1 pound-force foot/pound/°R = 0.0012850675 calorie (IT)/gram/°F
1 calorie (IT)/gram/°F = 778.16926227 pound-force foot/pound/°R
we use cross multiplication method
pound-force foot/pound/°R → calorie (IT)/gram/°F
1 → 0.0012850675
1.5 → ?( suppose x)
=>1.5*0.0012850675=1*x
by simplifying
x=0.0019276012