scruple (apothecary) to denarius (Biblical Roman)
Please provide values below to convert scruple (apothecary) [s.ap] to denarius (Biblical Roman), or change ↔.
scruple (apothecary) [s.ap]
Definition: An apothecary scruple is a unit of mass equal to 1/24 of a troy ounce or 1.2959782 grams.
Historyandorigin: It has historical origins in the Roman 'scrupulum.'
CurrentUse: It is used in the apothecary system.
funfact: The scruple is used in the apothecary system to measure small masses.
denarius (Biblical Roman)
Definition: A denarius is a unit of mass equal to approximately 3.26 grams.
Historyandorigin: It has historical origins in ancient Roman measurements.
CurrentUse: It is rarely used in modern times but can be found in historical contexts.
funfact: The denarius was used in ancient Roman for small mass measurements.
scruple (apothecary) [s.ap] to denarius (Biblical Roman) Conversion Table
1 scruple (apothecary) [s.ap] | 0.3366177143 denarius (Biblical Roman) |
2 scruple (apothecary) [s.ap] | 0.6732354286 denarius (Biblical Roman) |
3 scruple (apothecary) [s.ap] | 1.0098531429 denarius (Biblical Roman) |
5 scruple (apothecary) [s.ap] | 1.6830885714 denarius (Biblical Roman) |
10 scruple (apothecary) [s.ap] | 3.3661771429 denarius (Biblical Roman) |
50 scruple (apothecary) [s.ap] | 16.830885714 denarius (Biblical Roman) |
100 scruple (apothecary) [s.ap] | 33.661771429 denarius (Biblical Roman) |
1000 scruple (apothecary) [s.ap] | 336.61771429 denarius (Biblical Roman) |
10000 scruple (apothecary) [s.ap] | 3366.1771429 denarius (Biblical Roman) |
100000 scruple (apothecary) [s.ap] | 33661.771429 denarius (Biblical Roman) |
1000000 scruple (apothecary) [s.ap] | 336617.71429 denarius (Biblical Roman) |
How to Convert scruple (apothecary) to denarius (Biblical Roman)
1 scruple (apothecary) [s.ap] = 0.3366177143 denarius (Biblical Roman)
1 denarius (Biblical Roman) = 2.9707289829 scruple (apothecary) [s.ap]
we use cross multiplication method
scruple (apothecary) [s.ap] → denarius (Biblical Roman)
1 → 0.3366177143
1.5 → ?( suppose x)
=>1.5*0.3366177143=1*x
by simplifying
x=0.5049265714