joule/kilogram/K to calorie (IT)/gram/°F
Please provide values below to convert joule/kilogram/K [J/(kg*K)] to calorie (IT)/gram/°F, or change ↔.
joule/kilogram/K [J/(kg*K)]
Definition: The amount of heat required to raise the temperature of 1 kilogram of a substance by 1 Kelvin.
Historyandorigin: The SI unit of specific heat, derived from Joules, named after James Prescott Joule.
CurrentUse: Used in thermodynamics and material science to measure thermal energy storage in materials.
funfact: Water has a high specific heat capacity (4.18 J/g*K), which is why it takes a long time to boil!
calorie (IT)/gram/°F
Definition: Similar to the calorie (IT)/gram/°C, but using Fahrenheit for the temperature scale.
Historyandorigin: This unit was more common before the widespread adoption of Celsius for scientific measurements.
CurrentUse: Still found in some legacy systems for heat transfer calculations, particularly in older texts.
funfact: Though less common today, Fahrenheit-based calories were widely used in North America!
joule/kilogram/K [J/(kg*K)] to calorie (IT)/gram/°F Conversion Table
| 1 joule/kilogram/K [J/(kg*K)] | 0.0002388459 calorie (IT)/gram/°F |
| 2 joule/kilogram/K [J/(kg*K)] | 0.0004776918 calorie (IT)/gram/°F |
| 3 joule/kilogram/K [J/(kg*K)] | 0.0007165377 calorie (IT)/gram/°F |
| 5 joule/kilogram/K [J/(kg*K)] | 0.0011942295 calorie (IT)/gram/°F |
| 10 joule/kilogram/K [J/(kg*K)] | 0.002388459 calorie (IT)/gram/°F |
| 50 joule/kilogram/K [J/(kg*K)] | 0.0119422948 calorie (IT)/gram/°F |
| 100 joule/kilogram/K [J/(kg*K)] | 0.0238845897 calorie (IT)/gram/°F |
| 1000 joule/kilogram/K [J/(kg*K)] | 0.2388458966 calorie (IT)/gram/°F |
| 10000 joule/kilogram/K [J/(kg*K)] | 2.3884589663 calorie (IT)/gram/°F |
| 100000 joule/kilogram/K [J/(kg*K)] | 23.884589663 calorie (IT)/gram/°F |
| 1000000 joule/kilogram/K [J/(kg*K)] | 238.84589663 calorie (IT)/gram/°F |
How to Convert joule/kilogram/K to calorie (IT)/gram/°F
1 joule/kilogram/K [J/(kg*K)] = 0.0002388459 calorie (IT)/gram/°F
1 calorie (IT)/gram/°F = 4186.8 joule/kilogram/K [J/(kg*K)]
we use cross multiplication method
joule/kilogram/K [J/(kg*K)] → calorie (IT)/gram/°F
1 → 0.0002388459
1.5 → ?( suppose x)
=>1.5*0.0002388459=1*x
by simplifying
x=0.0003582688