calorie (IT)/gram/°F to joule/kilogram/°C
Please provide values below to convert calorie (IT)/gram/°F to joule/kilogram/°C [J/(kg*°C)], or change ↔.
calorie (IT)/gram/°F
Definition: Similar to the calorie (IT)/gram/°C, but using Fahrenheit for the temperature scale.
Historyandorigin: This unit was more common before the widespread adoption of Celsius for scientific measurements.
CurrentUse: Still found in some legacy systems for heat transfer calculations, particularly in older texts.
funfact: Though less common today, Fahrenheit-based calories were widely used in North America!
joule/kilogram/°C [J/(kg*°C)]
Definition: The same as J/(kg*K), but using degrees Celsius instead of Kelvin as the temperature unit.
Historyandorigin: Part of the SI system, derived from the metric system for measuring energy changes.
CurrentUse: Used in chemistry, physics, and engineering to analyze temperature effects in materials.
funfact: For many substances, specific heat is almost the same whether measured in °C or K, thanks to the proportionality!
calorie (IT)/gram/°F to joule/kilogram/°C [J/(kg*°C)] Conversion Table
| 1 calorie (IT)/gram/°F | 4186.8 joule/kilogram/°C [J/(kg*°C)] |
| 2 calorie (IT)/gram/°F | 8373.6 joule/kilogram/°C [J/(kg*°C)] |
| 3 calorie (IT)/gram/°F | 12560.4 joule/kilogram/°C [J/(kg*°C)] |
| 5 calorie (IT)/gram/°F | 20934 joule/kilogram/°C [J/(kg*°C)] |
| 10 calorie (IT)/gram/°F | 41868 joule/kilogram/°C [J/(kg*°C)] |
| 50 calorie (IT)/gram/°F | 209340 joule/kilogram/°C [J/(kg*°C)] |
| 100 calorie (IT)/gram/°F | 418680 joule/kilogram/°C [J/(kg*°C)] |
| 1000 calorie (IT)/gram/°F | 4186800 joule/kilogram/°C [J/(kg*°C)] |
| 10000 calorie (IT)/gram/°F | 41868000 joule/kilogram/°C [J/(kg*°C)] |
| 100000 calorie (IT)/gram/°F | 418680000 joule/kilogram/°C [J/(kg*°C)] |
| 1000000 calorie (IT)/gram/°F | 4186800000 joule/kilogram/°C [J/(kg*°C)] |
How to Convert calorie (IT)/gram/°F to joule/kilogram/°C
1 calorie (IT)/gram/°F = 4186.8 joule/kilogram/°C [J/(kg*°C)]
1 joule/kilogram/°C [J/(kg*°C)] = 0.0002388459 calorie (IT)/gram/°F
we use cross multiplication method
calorie (IT)/gram/°F → joule/kilogram/°C [J/(kg*°C)]
1 → 4186.8
1.5 → ?( suppose x)
=>1.5*4186.8=1*x
by simplifying
x=6280.2