Btu (IT)/pound/°R to joule/kilogram/K
Please provide values below to convert Btu (IT)/pound/°R to joule/kilogram/K [J/(kg*K)], or change ↔.
Btu (IT)/pound/°R
Definition: Btu per pound per degree Rankine, used in imperial thermodynamics.
Historyandorigin: The Rankine scale is used for absolute temperature measurements in thermodynamics.
CurrentUse: Found in specific legacy systems and applications requiring absolute temperature analysis.
funfact: Rankine and Kelvin are similar, but Rankine is used in imperial systems, while Kelvin is the standard in SI!
joule/kilogram/K [J/(kg*K)]
Definition: The amount of heat required to raise the temperature of 1 kilogram of a substance by 1 Kelvin.
Historyandorigin: The SI unit of specific heat, derived from Joules, named after James Prescott Joule.
CurrentUse: Used in thermodynamics and material science to measure thermal energy storage in materials.
funfact: Water has a high specific heat capacity (4.18 J/g*K), which is why it takes a long time to boil!
Btu (IT)/pound/°R to joule/kilogram/K [J/(kg*K)] Conversion Table
| 1 Btu (IT)/pound/°R | 4186.8 joule/kilogram/K [J/(kg*K)] |
| 2 Btu (IT)/pound/°R | 8373.6 joule/kilogram/K [J/(kg*K)] |
| 3 Btu (IT)/pound/°R | 12560.4 joule/kilogram/K [J/(kg*K)] |
| 5 Btu (IT)/pound/°R | 20934 joule/kilogram/K [J/(kg*K)] |
| 10 Btu (IT)/pound/°R | 41868 joule/kilogram/K [J/(kg*K)] |
| 50 Btu (IT)/pound/°R | 209340 joule/kilogram/K [J/(kg*K)] |
| 100 Btu (IT)/pound/°R | 418680 joule/kilogram/K [J/(kg*K)] |
| 1000 Btu (IT)/pound/°R | 4186800 joule/kilogram/K [J/(kg*K)] |
| 10000 Btu (IT)/pound/°R | 41868000 joule/kilogram/K [J/(kg*K)] |
| 100000 Btu (IT)/pound/°R | 418680000 joule/kilogram/K [J/(kg*K)] |
| 1000000 Btu (IT)/pound/°R | 4186800000 joule/kilogram/K [J/(kg*K)] |
How to Convert Btu (IT)/pound/°R to joule/kilogram/K
1 Btu (IT)/pound/°R = 4186.8 joule/kilogram/K [J/(kg*K)]
1 joule/kilogram/K [J/(kg*K)] = 0.0002388459 Btu (IT)/pound/°R
we use cross multiplication method
Btu (IT)/pound/°R → joule/kilogram/K [J/(kg*K)]
1 → 4186.8
1.5 → ?( suppose x)
=>1.5*4186.8=1*x
by simplifying
x=6280.2